5x^2+8x-40=8

Solution for 5x^2+8x-40=8 equation:

5x^2+8x-40=8

We move all terms to the left:

5x^2+8x-40-(8)=0

We add all the numbers together, and all the variables

5x^2+8x-48=0

a = 5; b = 8; c = -48;
Δ = b2-4ac
Δ = 82-4·5·(-48)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-32}{2*5}=\frac{-40}{10}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+32}{2*5}=\frac{24}{10}
=2+2/5
$